# Prof je bilmes ee596awinter 2013dgms lecture 9 feb 6th

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Unformatted text preview: 9.26) and also, when the ﬁrst diﬀerence between the 3rd and 2nd best is at time t, we have that for t &gt; t(2) , ∗ ∗ ∗ DQ1:T (1, t(2) , t) = q1:T : q1 = q1 (1), q2 = q2 (1), qt(2) −1 = qt(2) −1 (1), . . . , ∗ qt(2) = qt(2) (1), ∗ ∗ ∗ ∗ qt(2) = qt(2) (2), qt(2) +1 = qt(2) +1 (2), . . . , qt−1 = qt−1 (2), qt = qt (2) Prof. Jeﬀ Bilmes EE596A/Winter 2013/DGMs – Lecture 9 - Feb 6th, 2013 page (9.27) 9-23 (of 180) k-best without the penalty Island Summary Scratch Partitioning Thus, the blocks {DQ1:T (1, t)}t=t(2) and DQ1:T (1, t(2) , t) constitute the partitioning of DQ1:T \ {q1:T (1), q1:T (2)}. Prof. Jeﬀ Bilmes EE596A/Winter 2013/DGMs – Lecture 9 - Feb 6th, 2013 t≥t(2) page 9-24 (of 180) k-best without the penalty Island Summary Scratch Partitioning Thus, the blocks {DQ1:T (1, t)}t=t(2) and DQ1:T (1, t(2) , t) constitute the partitioning of DQ1:T \ {q1:T (1), q1:T (2)}. t≥t(2) Use same strategy as before: score each block (based on max path within), ﬁnd the (a) max, and then compute it withi...
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## This document was uploaded on 04/05/2014.

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