The basic pattern is 1 look at the current partition

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Unformatted text preview: (1, t )) ∗ maxq∈{q∗ (1),q∗ (2)} mt −1,t (qt −1 (2), q ) t t ∗ ∗ mt −1,t (qt −1 (2), qt (2)) (9.28) and for t > t(2) = t pm DQ1:T (1, t , t) = pm (DQ1:T (1, t )) ∗ maxq=qt (2) mt−1,t (qt−1 (2), q ) ∗ ∗ mt−1,t (qt−1 (2), qt (2)) (9.29) the third most probable sequence has probability ∗ p(q1:T (3), x1:T ) = max max pm (DQ1:T (1, t)), max pm (DQ1:T (1, t , t)) ¯ t:t=t t:t≥t (9.30) Given new best block, use dynamic programming again to identify it. Prof. Jeff Bilmes EE596A/Winter 2013/DGMs – Lecture 9 - Feb 6th, 2013 page 9-25 (of 180) k-best without the penalty Island Summary Scratch General case the same pattern as above, iterative procedure to construct the next best. Prof. Jeff Bilmes EE596A/Winter 2013/DGMs – Lecture 9 - Feb 6th, 2013 page 9-26 (of 180) k-best without the penalty Island Summary Scratch General case the same pattern as above, iterative procedure to construct the next best. The basic pattern is: Prof. Jeff Bilmes EE596A/Winter 2013/DGMs – Lectur...
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This document was uploaded on 04/05/2014.

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