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Quiz 1 Solution Fall 2013

# Quiz 1 Solution Fall 2013 - PHYS-100 QUIZ-I MAX TIME 35 min...

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PHYS-100 QUIZ-I MAX. TIME : 35 min. Name___________________________ Rec. Sec. No.____________ _______________________________________________________________________ A = π r 2 ( θ /360); c = 2 π r ; A = ab/2 ; l = r θ ; a 2 +b 2 = h 2 Area of a trapezoid = h (b 1 +b 2 )/2 Note: Diagrams are not drawn to scale Prob.1 ( 10 pts). The shaded shape outlined in bold is cut out from a thin sheet of metal. Find the angle θ for R = 15.0 cm and r = 10.0 cm if the area of the figure is 344 cm 2 . The area of the figure is: ( π R 2 π R 2 θ 360 ) ( π r 2 π r 2 θ 360 ) = π ( R 2 r 2 )(1 θ 360 ) = 344 cm 2 Solving for θ we get: θ = 360 1 344 cm 2 π ( R 2 r 2 ) = 45

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Prob.2 ( 10 pts. ). The area of the triangle
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