problem19_48

University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.48: Path ac has constant pressure, so , T nR V p W ac = = and ) ( c a ac T T nR W - = J. 10 4.789 K) 300 K K)(492 mol J 5 mol)(8.314 3 ( 3 × = - = Path cb is adiabatic , so ), 0 ( T nC U U Q W Q V cb - = - = - = = and using , R C C p V - = ) )( ( c T T R C n W b p cb - - - = J. 10 735 . 6 K) 492 K K)(600 mol J 3145 . 8 K mol J mol)(29.1 3 ( 3 × - = -
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Unformatted text preview: -= Path ba has constant volume, so . = ba W So the total work done is ba cb ac W W W W + + = J 10 735 . 6 J 10 789 . 4 3 3 + ×-× = J. 10 95 . 1 3 ×-=...
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