{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

10b - TreesSlides

# We showed how a doubly linked list helps here so what

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . So what happens if we do keep a parent pointer, as well as left and right child pointers, in each node. The first node in inorder traversal is the left-most leftnode. struct node { void* data; curr = root; while (curr->left != 0) (currcurr = curr->left; curr- nodePtr parent, left, right; parent left right; }; All the insertion and deletion code would now be rewritten to update the parent pointer as well as parent the child pointers. But traversal is now very simple. if (curr->right != 0) // into right subtree (curr{ curr = curr->right; currwhile (curr->left != 0) (currcurr = curr->left; curr} If it If it has no right subtree and no parent, we're at the root of a tree with only a left subtree so we're finished. else if (curr->parent == 0) (currcurr = 0; Now let's suppose that at some time during the traversal we are at node curr. curr If it has a right child, we find the left-most node in leftthe right subtree. Otherwise the current node is the rightmost node of subtree. We look for an ancestor who has t...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online