Unformatted text preview: ult;
}
Applied Programming int ListDataCmp(const Video& v1,
const Video& v2)
{
int result = strcmp(v1.Title,
v2.Title);
if (result == 0)
{
if (v1.Year > v2.Year)
result = 1;
result
else if (v1.Year < v2.Year)
result = 1;
}
return result;
}
Applied Programming In C++ this would be
nodePtr curr;
curr = head;
while (curr!= 0 &&
!=
ListDataCmp(newdata,curr>data) >= 0)
ListDataCmp(newdata,curr
curr = curr>next;
curr
if (curr != 0)
// goes before curr
//
curr
else
// goes at the end Unfortunately, we need to be able to link the new
Unfortunately,
node to the one before curr, so we have to
curr so
remember the previous node.
remember
Applied Programming Applied Programming nodePtr curr, prev;
prev Here's our diagram of the list so far. curr = head;
prev = 0;
while (curr != 0 &&
ListDataCmp(newdata,curr>data) >= 0)
{
prev = curr;
curr
curr = curr>next;
curr
}
//
//
//
//
//
//
//
// new node goes
if prev is 0,
prev is
so we have to
if curr is 0,
curr after prev and
prev and
it goes on the
change head as
it is going on Head
1 2 3 6
0 4 Let's see how we go about adding a new
Let's
data item.
data before curr
curr
head of list
well
the end Suppose we want to add 5. Applied Programming Applied Programming We firstly create a new node for the list. We now find where it goes. Head Head
1 2 3 6
0 4 (prev)
1 2 4 3 (curr)
6
0 (newnode) Let's put it here in our
diagram. 5 We will ultimately get values for
curr and prev.
and prev W e don't need to put a value in next.
We
next All these are pointers, of course. Applied Programming Note that prev>next iis equal to curr.
s
Note
prev
curr
Head
2 3 Applied Programming If we were adding to the head of the list prev is 0.
If
prev (prev)
1 5 (curr) 4 Head (curr) 6
0 (newnode)
5 So we want the pointers to finally look like this.
Applied Programming 1 2 3 4 6
0 (newnode)
0 So
prev>next = newnode;
>next
newnode
newnode>next = curr;
>next
curr
head = newnode;
head
newnode
Applied Programming So the final code fragment is // So now sorti...
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 Spring '14
 Computer Science, curr

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