8a - Collections

# 0 472 1 432 2 254 3 534 4 654 5 477 6 459 649 7 239 8

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Unformatted text preview: ger keys have to be coded into nteger integer values. integer Consider the following data 459, 254, 472, 534, 649, 239, 432, 654, 477 The method involves successive sorts of a list. Applied Programming Here's our initial list, and our bins. 0 459 1 254 2 472 432 472 3 534 4 254 534 654 649 5 239 6 432 654 7 477 477 8 9 459 649 239 Applied Programming Now we take these values back out of the bins and into our list. 0 472 1 432 2 254 3 534 4 654 5 477 6 459 649 7 239 8 9 Applied Programming Applied Programming Now we take these values back out of the bins and into our list. 0 472 1 432 2 472 432 254 3 534 4 254 534 654 654 5 477 6 459 649 7 477 239 8 9 459 649 239 Applied Programming Now we put them in the bins according to their Now tens digit. tens 0 472 1 432 2 254 3 432 534 239 534 4 649 654 5 254 654 459 477 6 459 649 7 472 477 239 8 9 Applied Programming Now we take them back out again. 432 534 239 649 254 654 459 472 477 0 1 2 3 432 534 239 4 649 5 254 654 459 6 7 472 477 8 9 Applied Programming Now we take them back out again. And put them in by hundreds digit. 0 1 2 239 254 3 4 432 459 472 477 5 534 6 649 654 7 You know what the last step is. 8 9 Applied Programming Now we take them back out again. And put them in by hundreds digit. 0 432 1 534 2 239 254 239 3 649 4 432 459 472 477 254 5 534 654 6 649 654 459 472 7 You know what the last step is. 477 8 9 Applied Programming 239 254 432 459 472 477 534 649 654 Now sorted. Each shuffle involves n operations. Number of passes is dependent on the size Number of the numbers – constant. So the sort is O(n). So O(n But the constant of proportionality might But make radix sort worse than O(nlog n) sorts. O(nlog Applied Programming...
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## This document was uploaded on 04/07/2014.

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