Unformatted text preview: Solutions to Homework Assignment 4 MATH 24901 and 02 Section 12.4, Page 820 17, 912, 14, 15, 25, 26, 30, 31, 34, 35, 36, 45 4. < 1 , 1 , 1 > × < 1 , 1 , 1 > = < 1(1) (1)(1) , [1(1) 1(1)] , 1(1) ( 1)(1) > = < 2 , , 2 > . You can check the orthogonality. 6. < 1 , e t , e t > × < 2 , e t , e t > = < e t ( e t ) e t ( e t ) , [1( e t ) e t (2)] , 1( e t ) e t (2) > = < 2 , 3 e t , e t > . 9. Only (a), (c), and (f) are meaningful. The others are all attempting to take a cross product in which at least one factor is a scalar. 10.  u × v  = 5 · 10 sin(60 ◦ ) = 25 √ 3 . According to the righthand rule, it will be directed into the page. 12. (a) Since the zaxis is perpendicular to the xyplane, we have  a × b  = 3(2) sin(90) = 6 . (b) The cross product is in the xyplane, so the zcomponent is 0. It is also going to be in the second quadrant (using the righthand rule), so its xcomponent is positive and its ycomponent is negative....
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 Spring '08
 Starr
 Math, Dot Product, Righthand rule, Pseudovector

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