Unformatted text preview: lgium, the Netherlands, and Luxembourg (4, 2,
2, 1)
Case 2b: Italy, Belgium, the Netherlands, and Luxembourg (4,2,2, 1)
Case 2c: Germany, Italy, and Luxembourg (4, 4, 1) For each of the three above subcases we can use counting techniques
to …gure out the number of ways this can happen.
Case 2a: 4!1! = 24
Case 2b: 4!3! = 24
Case 2c: 3!2! = 12 Thus, the total number of pivotal orderings for case 2 (9 votes) is
24 + 24 + 12 = 60. Van Essen (U of A) Power 18 / 22 Case 3: Exactly ten votes precede France How can we get 10 votes? If France is preceded by:
Case 3a: Germany, Italy, and Belgium (4, 4, 2)
Case 3b: Germany, Italy, and the Netherlands (4, 4, 2) For each of the three above subcases we can use counting techniques
to …gure out the number of ways this can happen.
Case 3a: 3!2! = 12
Case 3b: 3!2! = 12 Thus, the total number of pivotal orderings for case 3 (10 votes) is 24 Van Essen (U of A) Power 19 / 22 Case 4: Exactly eleven votes precede France How can we get 11 votes? If France is preceded by:
Case 4a: Germany, Italy, Belgium, and Luxembourg (4, 4, 2,1)
Case 4b: Germany, Italy, the Netherlands, and Luxembourg (4, 4, 2,1) For each of the three above subcases we can use counting techniques
to …gure out the number of ways this can happen.
Case 4a: 4!1! = 24
Case 4b: 4!1! = 24 Thus, the total number of pivotal orderings for case 4 (11 votes) is 88 Van Essen (U of A) Power 20 / 22 SSI for France The total number of pivotal orderings is 36 + 60 + 24 + 48 = 168
The total number of distinct orderings is 720
Thus, the ShapleyShubik index for France is
SSI (France ) = Van Essen (U of A) Power 168
14
=
720
60 21 / 22 SSI for EEC Country
Germany
Italy
France
Belgium
Netherlands
Luxembourg Van Essen (U of A) Votes
4
4
4
2
2
1 Power SSI
14
60
14
60
14
60
9
60
9
60
0
60 22 / 22...
View
Full
Document
This note was uploaded on 04/08/2014 for the course ECON 497 taught by Professor Vanessen during the Spring '12 term at Alabama.
 Spring '12
 Vanessen
 The Land

Click to edit the document details