Horizontal Curves

Compute the degree of curvature degree tangent

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Unformatted text preview: of N 40° 10’ 20” E at PI STA 6 + 26.57. A horizontal curve with radius = 1000 40° 10’ 20” feet will be used to connect the two tangents. Compute the degree of curvature, degree tangent distance, length of curve, chord distance, middle ordinate, external ordinate, distance, PC and PT Stations. Solution: PC STA = PI STA – T = 626.57 – 146.18 = PC STA 4 + 80.39 PT STA = PC STA + L = 480.39 + 290.31 = PT STA 7 + 70.70 Final thoughts: Given the coordinates of the PI can you compute the coordinates of the PC? How about the PT? Can you compute the coordinates of the center of the circle? Curve Layout by Deflection Angles 5 Subchords and Subdeflections 6...
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This note was uploaded on 04/05/2014 for the course CE 115 taught by Professor Mcginni during the Fall '14 term at Christian Brothers.

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