ME 471 - Midterm Exam 1 Solutions

3 introduction to aerodynamics department of

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Unformatted text preview: Introduction to Aerodynamics Department of Mechanical Engineering Winter 2014 Instructor – Rajat Chakravarty Midterm Examination Equation Sheet TE TE LE LE N Pu cos u sin dsu A TE P sin u u cos dsu LE M LE u l l sin dsl l cos dsl TE P sin l LE TE P cos P cos u sin x Pu sin u cos y dsu LE TE P cos l l sin x Pl sin l cos y dsl LE c c 1 C P,l C P,u dx c f ,u dyu c f ,l dyl dx c dx dx 0 0 c c dy dy 1 c a C P ,u u C P ,l l dx c f ,u c f ,l dx c 0 dx dx 0 c c dy dy 1 c mLE 2 C P ,u C P ,l xdx c f ,u u c f ,l l xdx dx dx c 0 0 c c dy u dy 1 2 C P ,u c f ,u y u dx C P ,l l c f ,l y l dx dx dx c 0 0 cl c n cos c a sin c d c n sin c a cos M M xcp LE LE N L 2 a0 CL CL C D cd i a eAR e1 AR a0 1 e AR 1 cn 2 0 2 0 u v y x x y 1 1 2 2 r r r r r 2 2 z 2 1 1 vr v r r r r u u 1 u z u r r z r z z r 2 1 ru u r r r z Additional Information Rair = 287 J·kg-1·K-1 Sutherland Law (for viscosity of air): 3/ 2 T T0 S -5 2 T T S , where Sair ≈ 110.4 K, T0 = 273 K, μ0 = 1.71×10 Ns/m , and T is in [K] 0 0...
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This document was uploaded on 03/30/2014 for the course ME 471 at Maryland.

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