DMC Evaluation Quiz Solution

# DMC Evaluation Quiz Solution - MAE 342 Design of Mechanical...

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M A E 342 - Design of Mechanical Components Solutions to Evaluation Quiz 1: In Figure 1, for static equilibrium, F 2 must be (circle the correct answer): (a) 10 N, (b) 10 30 0 tan( ) N, (c) 10 30 0 cot( ) N, (d) cannot be determined. For a force balance in horizontal direction: F 1 30 10 cos = . For a force balance in vertical direction: FF 12 30 sin = . Eliminating F 1 : F 2 10 30 = tan . 30 0 10 N F 1 F 2 1 N 1 N A A Section A-A 0.1 mm 0.2 mm Figure 1 Figure 2 2. In Figure 2, the stress in X-section A-A (assumed to be uniform) is 50 N/mm 2 . Stress = Force/ Area (Stress is proportional to force but inversely proportional to the area. Makes sense?). σ = = 1 01 0 2 50 /( .* . ) 3. In Figure 2, if the Young’s modulus (E) of the material is 50,000 N/mm 2 , and the length of the bar is 100 mm, the increase in length of the bar is approximately 0.1 mm. Increase in length is proportional to strain and total length. ll = ε Strain is unit-less, and is proportional to stress but inversely proportional to Young’s Modulus, since Young’s modulus is a measure of the material’s stiffness.

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## This note was uploaded on 04/07/2008 for the course MECHANICAL 342 taught by Professor Baruh during the Spring '07 term at Rutgers.

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DMC Evaluation Quiz Solution - MAE 342 Design of Mechanical...

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