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Unformatted text preview: 650:351 Thermodynamics Doyle Knight Department of Mechanical and Aerospace Engineering Rutgers  The State University of New Jersey New Brunswick, NJ USA Tel: 732 445 4464 Email: doyleknight@gmail.com Office hours: Tuesday and Friday, 10:30 am to 12 noon and by appointment Homework Assignment No. 2 Problem 3.21 Modern extraction techniques are based on dissolving material in supercritical fluids such as carbon dioxide. How high are the pressure and density of carbon dioxide when the pressure and temperature are around the critical point ? Repeat for ethyl alcohol. Solution From Table A.2, the specific volume for carbon dioxide at the critical condition is v = 2 . 12 10 3 m 3 /kg. Therefore, = v 1 = 471 . 6 kg/m 3 Similarly, for ethyl alcohol at critical conditions, v = 3 . 63 10 3 m 3 /kg. Thus, = v 1 = 275 . 5 kg/m 3 650:351 Thermodynamics Page 1 Homework Assignment No. 2 Problem 3.29 Determine the phase of the substance at the given state using Appendix B tables a) Water at 100 C and 500 kPa From Table B.1.1, for saturated liquidvapor water at T = 100 C the pressure is p = 101 . 3 kPa. Since p = 500 kPa is greater than this pressure, it is a compressed liquid. b) Ammonia at 10 C and 150 kPa From Table B.2.1, for saturated liquidvapor am monia at T = 10 C the pressure is p = 290 . 9 kPa. Since p = 150 kPa is less than this pressure, it is superheated vapor. c) R12 at 0 C and 350 kPa From Table B.3.1, for saturated liquidvapor R12 at T = 0 C the pressure is p = 308 . 6 kPa. Since p = 350 kPa is greater than this pressure, it is a compressed liquid. 650:351 Thermodynamics Page 2 Homework Assignment No. 2 Problem 3.36 Determine the phase and specific volume a) R22 at T = 25 C and p = 100 kPa From Table B.4.1, at saturated conditions for T = 25 C the pressure is p = 201 kPa. Thus,= 201 kPa....
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This homework help was uploaded on 04/07/2008 for the course MECHANICAL 351 taught by Professor Knight during the Spring '08 term at Rutgers.
 Spring '08
 Knight

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