Electricity and Magnetism Final

Electricity and - c 0 e E= 2kA 3a o I 5 Determine current through resistor R3 E1=E3=3V E2=2V All resistors are lQ r" R1:f S'1 J 1 0)13 =-Q 3 b

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1. A charge +4q is located at the origin an a charge -q is on the x axis at x=a. An expression describing potential on the x-axis for x>a is V,(x)~\K~ (~ - ~~ CA~ ~ - K~ l~ - r~) d ) v(x)~kq ( ~+~ ) x x-a a) V(x)-kq ( ~+~ ) x x+a b ) v(x)- kq ( ~ -~ ) c x x+a 2. Assume that all capacitors are uncharged before the circuit is assembled. The potential along the bottom wire is defined to be zero. The voltage Vbat the point labeled b is: 12 V b I I ~ -t- ----- ./ 2 V \lV:: > - <y V ~ ~I::. . C ~ { L lpl.- . 7-- 1
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3. The charging of individual raindrops is ultimately responsible for the electrical activity of a thunderstorm. Suppose two drops with equal charge q are located on the x axis at +/- a. Find the magnitude of the electric force on a third drop with charge Q located at an arbitrary point on the YaxIS. a) F = k1jQ . 2(a + yJ d) F = k1jQ (a + yJ c) F = 2k1jQ (a + yJ 4. A semicircular loop of radius a carries positive charge Q distributed uniformly over its length with the line density A.What is the electric field at the center of the loop?
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Unformatted text preview: c) 0 e) E= 2kA 3a o I -. 5. Determine current through resistor R3. E1=E3=3V, E2=2V. All resistors are lQ. r--.. . .--"\ , , R1 :f S'1-,. J 1 0)13 =-Q 3 b) 13 = 0 2 c) 13 = - Q 3 5 d)13 =-Q 3 7 e) 13 =-Q 3 €rzt.fr ~D 17~ /&/~ 6. The circuit below c through RI afte~th .-E .tainsa battery, a switch, a capacitor and two resistors. Find the current itch hafbeen closed for a long time. 6 o R1 v--1R S-:Y--1. ~ 7. Two cylindrical resistors are made from the same material, and they are equal in length. The first resistor has diaineter d, and the second resistor .a ter 2d. If the same CUlTent flows through both resistors, compare the average veloc. les of the el ctrons in the two resistors: a) V2=0.5 VI 1~b) v2=2vI T e) V2=4 VI l...
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This note was uploaded on 04/07/2008 for the course BENG 130, 103B, taught by Professor Gough during the Spring '08 term at UCSD.

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Electricity and - c 0 e E= 2kA 3a o I 5 Determine current through resistor R3 E1=E3=3V E2=2V All resistors are lQ r" R1:f S'1 J 1 0)13 =-Q 3 b

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