problem15_39

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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15.39: a) b) Eq. (15.28) gives the general equation for a standing wave on a string: ωt kx A t x y sin ) sin ( ) , ( sw = cm 80 . 2 2 ) cm 60 . 5 ( 2 so , 2 SW sw = = = = A A A A c) The sketch in part (a) shows that ) 2 ( 3 λ = L k π π k 2 , 2 = λ λ = Comparison of ) , ( t x y given in the problem to Eq.(15.28) gives cm. rad 0340 . 0 = k So, cm .8 184 ) cm rad 0340 . 0 ( 2 = = λ π cm 277 ) 3 ( 3 = λ = L d) (c) part from cm, 185 = λ Hz 96 . 7 2 so s rad 0 . 50 = = = π ω f ω period s 126 . 0 1 = = f T s cm 1470 = λ = f v e) ωt kx ωA dt dy v y cos sin sw = = s cm 280 cm) s)(5.60 rad 0 . 50 ( SW max , =

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problem15_39 - 15.39 a b Eq(15.28 gives the general...

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