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HW 2 Solutions (Page 8)

# HW 2 Solutions (Page 8) - anti-Q a Let f = number of...

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Unformatted text preview: anti-Q a) Let f = number of full-time consultants working the morning shift (8 a.m.-4 p.m.), f = number of full-time consultants working the afternoon shift (12 p.m.-8 pm). 1: = number of full-time consultants working the evening shift (4 p.m.~midnight), p] = number of part-time consultants working the first shift (8 a.m.-12 p.m.), p1 = number of part-time consultants working the second shift (12 p.m.-4 p.m.), p1 = number of part-time consultants working the third shift (4 p.m.-8 p.m.), p4 = number of part-time consultants working the fourth shift (8 p.m.-midnight). Minimize c= (\$14 / hour)(8 hours)”. + j; + f,]+ (\$5 I hour)(4 hi:)urs)[pl + p2 + 1123 + p‘], subject to 1‘] +191 24 fi+fi+P228 f2+f3+p3210 flit-[1‘26 1222p. fi+f222Pz fz+f322P3 £22104 and ﬁEO. £20, 1320, p120, p220. p320, p420. b) Beneﬁt Contribution Per Unit of Each Activity Minimum FT1 FT2 Fl'3 PT1 PT2 PTS PT4 Required B sm-12 noon 4 2 4 4 2 0 noon-4 pm a 2 8 B 2 O 4 pm-8 pm 10 2 10 10 2 O B pm-mtdnight 6 2 6 6 2 0 Unit Cost Solution ...
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