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**Unformatted text preview: **y v L m vt ) ) (( and equating the expressions, canceling a factor of t and solving for . gives 2 2 m k L v v ′ = An equivalent method is to use the result of Problem 11.82(a), which relates the force constant k ′ and the “Young’s modulus” of the Slinky . or , , A L k Y L YA k TM ′ = = ′ The mass density is (16.8) Eq. and ), ( AL m ρ = gives the result immediately. b) s. m 90 . 4 ) kg 250 . ( ) m N 50 . 1 ( ) m 00 . 2 ( =...

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