problem15_83

University Physics with Modern Physics with Mastering Physics (11th Edition)

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15.83: a) For a string, μ F L n n f 2 = and in this case, . 1 = n Rearranging this and solving for F gives , that Note . 4 2 2 2 ρ πr μ f L μ F = = m. kg 10 01 . 1 ) m kg 7800 ( m) 10 203 (. so 3 3 2 3 - - × = × = π μ Substituting values, N. 4 . 99 Hz) 0 . 247 ( m) m)4(.635 kg 10 01 . 1 ( 2 2 3 = × = - F b) To find the fractional change in the frequency we must take the ration of : to f f , 2 1 μ F L f = ( 29 , 2 1 2 1 2 1 = = F μ L μ F L f ( 29 2 1 2 1 F μ L f = . 2 1 2 1 F F μ L f = Now divide both sides by the original equation for f and cancel terms: F F f f f f μ F L F F μ L Δ 2 1 2 1 2 1 2 1 = = c)
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This document was uploaded on 02/05/2008.

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