ch4 problem40

Physics: Principles with Applications

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=4pr40&id=489216 Chapter 4, Problem 40 Question Problem The forces acting on the car are the force of gravity which points vertically downwards, the normal force perpendicular to the road surface, and the frictional force parallel to the road surface. In reality, the four wheels support the car against the road surface, and the above forces are distributed among the four wheels and the road surface. However, for convenience of calculations, let us represent the car as a single block resting on a sloping surface. We know that and . We choose the x axis along the road surface, positive pointing down-slope. The components of in the x and y directions are Applying Newton s second law to the x direction, the acceleration in the x direction is directly
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: proportional to the net force in that direction, and inversely proportional to the mass of the car. Since the car is stationary on the slope, . Therefore, http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=4pr40&id=489216 (1 of 2) [2/4/2008 4:04:57 PM] http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=4pr40&id=489216 Applying Newton ’ s second law to the y direction Since the car is stationary, . Substitute for in equation (1). Divide both the sides by . In this condition, the forces are balanced and the car just about manages to remain stationary without sliding down. Solve for . So, we can leave a car parked on a slope that is up to inclined to the horizontal. http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=4pr40&id=489216 (2 of 2) [2/4/2008 4:04:57 PM]...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern