ch5 problem15

# Physics: Principles with Applications

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Chapter 5, Problem 15 Question Problem The forces acting on the passengers at the topmost point are the force of gravity due to the weight of the passengers, and the normal force exerted on the passengers by the wheel. The centripetal acceleration is along the negative axis. Draw a free body diagram showing the forces on the passengers and the direction of the centripetal acceleration. Let be the linear speed of the Ferris wheel and let be its radius. The centripetal force exerted on the passengers can be calculated using the equation . Choose the axis to be negative downwards. The net force acting along the axis can be calculated using the equation for the Newton s second law. The passengers would feel weightless when the normal force exerted on them by the wheel is zero. Substitute 0 for

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Unformatted text preview: , and solve for . It is given that the diameter of the Ferris wheel is 15 m. Find . Substitute 7.5 m for , for , and find . Find the frequency of the wheel using the equation http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=5pr15&id=489216 (1 of 2) [2/4/2008 4:13:43 PM] http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=5pr15&id=489216 where is the angular velocity of the wheel. The angular velocity and the linear speed are connected by the equation . Substitute for in the equation for the angular velocity, and solve for . Substitute for and 7.5 m for . Express the frequency in revolutions per minute. Thus, the Ferris wheel would need to make so that the passengers would feel “ weightless ” at the topmost point. http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=5pr15&id=489216 (2 of 2) [2/4/2008 4:13:43 PM]...
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## This document was uploaded on 02/05/2008.

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ch5 problem15 - and solve for It is given that the diameter...

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