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**Unformatted text preview: **If we ignore air resistance (a very good approximation), the total mechanical energy for the water balloon is conserved, ie, KE1 + PE1 = KE2 + PE2. Therefore we have: 1 2 1 2 mv1 + mgy1 = mv2 + mgy2 2 2 The mass cancels out and we have: 2 2 v2 = v1 + g ( y1 - y 2 )
Since the three balloons are launched with the same initial speed (same v1), from the same position (same y1), and land at the same level (same y2), the final speed (v2) for the three balloons will be the same. Note the result is independent of the masses of the balloons because the mass cancels out. ...

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