code.tex - \documentclass[conference]{IEEEtran}...

\documentclass[conference]{IEEEtran}
\documentclass{article}
\IEEEoverridecommandlockouts
% The preceding line is only needed to identify funding in the first footnote.
If that is unneeded, please comment it out.
\usepackage{cite}
\usepackage{amsmath,amssymb,amsfonts}
\usepackage{graphicx}
\usepackage{textcomp}
\usepackage{xcolor}
\usepackage{titlesec}
\usepackage{textcomp}
\usepackage{epsfig}
\usepackage{algpseudocode}
\usepackage{pgfplots}
\usepackage{tikz}
\usepackage{hyperref}
\usepackage{graphicx}
\usepackage{enumitem}
\usepackage[utf8]{inputenc}
\pgfplotsset{width=10cm,compat=1.9}
\usepgfplotslibrary{external}
\usepackage[linesnumbered,ruled,vlined]{algorithm2e}
\def\BibTeX{{\rm B\kern-.05em{\sc i\kern-.025em b}\kern-.08em
T\kern-.1667em\lower.7ex\hbox{E}\kern-.125emX}}
\usepackage[ruled,vlined]{algorithm2e}
\tikzexternalize
\begin{document}
\title{Implement Strassen’s Matrix Algorithm \\
\text{\Large{DAA ASSIGNMENT-4 , GROUP 6}}
}
\author{\IEEEauthorblockN{Shreyansh Patidar}
\IEEEauthorblockA{ \text{IIT2019018}}
\and
\IEEEauthorblockN{Biswajeet Das}
\IEEEauthorblockA{ \text{IIT2019019}}
\and
\IEEEauthorblockN{Hritik Sharma}
\IEEEauthorblockA{ \text{IIT2019020}}
}
\maketitle
{\textbf{\textit{Abstract:In this paper we have devised an algorithm which is an
implementation of Strassen’s matrix algorithm using divide and
conquer.\\
\\This report further contains-
\begin{enumerate}[label=(\Roman*)]
\item Algorithm Design
\item Algorithm Analysis
\item Result
\item Conclusion
\end{enumerate}
}}}
\maketitle
\section{INTRODUCTION}

In this report, we are going to discuss strassen matrix multiplication,formula
of matrix multiplication and algorithms for strassen matrix multiplication.
Let us consider two matrices X and Y. We want to calculate the resultant matrix
Z by multiplying X and Y. Matrix multiplication is a \href
{}{binary operation} that produces
a \href{(mathematics)}{matrix} from two
matrices. For matrix multiplication, the number of columns in the first matrix
must be equal to the number of rows in the second matrix. The resulting matrix,