ch7 problem40

Physics: Principles with Applications

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 7, Problem 40 Question Problem Since the nucleus was at rest before decay, its initial momentum was zero. By the law of conservation of momentum, the total of the momenta of the particles after decay will be zero too. Since the total momentum is conserved, its components in the x and y directions also are conserved. The x component of momentum conservation gives: Rearranging, we get: Similarly, the y component of momentum conservation gives: Rearranging, we get:
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Divide equation (1) by equation (2) to find . http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=7pr40&id= (1 of 2) [2/4/2008 5:06:24 PM] http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=7pr40&id= Substitute the value of in equation (1) or (2) to find . Therefore, the momentum of the second nucleus has a magnitude of and its direction is clockwise from the direction of the electron. http://www.hwproblems.com/cgi-bin/book.cgi?bookid=0044&cptn=7pr40&id= (2 of 2) [2/4/2008 5:06:24 PM]...
View Full Document

Page1 / 2

ch7 problem40 - Divide equation (1) by equation (2) to find...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online