lab 3 Calculations(mine)

lab 3 Calculations(mine) - Calculations C(Cu(NO3)2) = .157...

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Calculations C(Cu(NO 3 ) 2 ) = .157 m(Cu)theoretical = .157 x .025 x 63.55 = .2494g m(Cu)practical = 60.613 – 60.395 = .218g .218 / .2494 = .87397 x 100 = Results and Discussion 1) It is possible that excess compounds could still be left stuck to the copper. Also, there may have been some water not visible to the eye that could result in a larger mass. 2) .305g x 1 mol Cu x 1mol Cu 3 (PO 4 ) 2 x 380.59 g Cu 3 (PO 4 ) 2 = .609 g 63.55 g Cu 3 mol g Cu 1 mol Cu 3 (PO 4 ) 2 Cu 3 (PO 4 ) 2 When trying to decant the solution, some of the precipitate may have left the solution 3) The phosphate turns into phosphoric acid after HCl is added to the copper phosphate through a chemical reaction. A) After adding 2 ml of concentrated NaOH (6M), a Cu(OH) 2 formed turning the solution to a gelatinous solution, turquoise in color. Red litmus paper turned a dark blue showing that the solution is basic. B) All precipitate dissolved after adding H
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This lab report was uploaded on 04/10/2008 for the course CHEM 112 taught by Professor Jursich during the Spring '08 term at Ill. Chicago.

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lab 3 Calculations(mine) - Calculations C(Cu(NO3)2) = .157...

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