Unformatted text preview: Decanting was used for the solution. B) Upon adding H 2 SO 4 (3M), all precipitate was dissolved. The color of Cu(OH) 2 turned a light blue/turquoise color after it became diluted with H2SO4. CuSO 4 was formed. C) The addition of NaOH (6M), by dropping, neutralized the excess H2SO4 according to the following equation: 2NaOH + H 2 SO 4-> Na 2 SO 4 + 2H 2 O. 10 ml of Na 3 PO 4 (.5M) was added to the neutralized solution, turning it light blue and into Cu 3 (PO 4 ) 2 . The solution became basic after the addition of 2 ml of NaOH (6M). D) 10 ml of HCl was added to the solution from part C which dissolved the precipitate. The color changed to less diluted blue/turquoise color. E) From the copper(II) chloride solution, the addition of magnesium displaces copper from the copper(II) chloride. Hydrochloric acid dissolves the excess magnesium, creating hydrogen gas, and inducing the transparency of the solution. 87.4% yield...
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This lab report was uploaded on 04/10/2008 for the course CHEM 112 taught by Professor Jursich during the Spring '08 term at Ill. Chicago.
- Spring '08