1.
a)
n x P(+)= 100 x .05= 5
b)The probability that no women in sample have a mutation of BRCA1 is .005920.
c) The probability that atleast one of the 100 women has a mutation of BRCA1 is .994079.
d) The probability that 10 or more women in the sample have a mutation of BRCA1 is .028188.
e)The probability that exactly 10 women have a mutation of BRCA1 is .016715.
f) The probability that at most 3 women in the sample have BRCA1 mutation is .257839.
g) This finding impacts the validity of our assumption of a binomial distribution for BRCA1
mutations in women because it means that the probability of have a BRCA1 mutation is not the
same for all members of the population since the age of onset of breast cancer affects the
probability of having the mutation.
h) The finding that there are 10 pairs of sisters in the sample means that the trials are not
independent of one another since the sisters share the same genetic material and therefore are
likely to share the same probability of having the mutation gene or not. So within the population
of women in the US the probability is 50/50 of having the mutation, but if a family is
predisposed to having the condition then the probability could be .75 within that family.
2.
a)
c) The mean of the weights in the sample is 65.96 kg, the standard deviation is 13.109kg. These
values are different from 65 and 16 because is a random sample of the population therefore it has
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 Fall '08
 Johnson
 Normal Distribution, Standard Deviation

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