Quiz 1 MyStatLab First Attempt (83%)

Quiz 1 MyStatLab First Attempt (83%) - University of...

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Unformatted text preview: Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 1, Suppose that you measure the time it takes to download a video from the intemet. a. Explain why the download time is a continuous numerical variable. b. Explain why the download time is a ratio scaled variable. a. Choose the correct answer below. 9! A. Download time is a continuous numerical variable because it has numerical values that arise from a counting process. r]? B. Download time is a continuous numerical variable because it has numerical values that arise from a measuring process. :j:j:-C. Download time is a continuous numerical variable because it has values that can only be placed into categories. b. Choose the correct answer below. :j :-A. Download times are categories in which no ranking is implied. :j'j:- B. Download times are numerical values that imply order but do not specify the amount of additional time that is added between higher levels. :j :-C. Download times are numerical values that imply order and the difference between the times is meaningful, but it does not have a true zero point. ‘33-! D. Download times are numerical values that imply order and also have a true zero point. YOU ANSWERED: A Page 1 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 2, The standardized test scores from a sample of 50 applicants to a masters program indicate that none of the applicants scored below 450. A frequency distribution was formed by choosing class intervals 450 to 499, 500 to 549, and so on, with the last class having an interval from 700 to 749. Two applicants scored in the interval 450 to 499, and 7 applicants scored in the interval 500 to 549. Complete parts (a) through (d). a. What percentage of applicants scored below 500‘? 4 % b. What percentage of applicants scored between 500 and 549'? 14 % c. What percentage of applicants scored below 550‘? 18 % d. What percentage of applicants scored below 750? 100 % 3, The following is a set of data for a population with N = 10. 611314510139119% 3. Compute the population mean. b. Compute the population standard deviation. 3. The population mean is u= 9.1 . (Type an integer or a decimal.) b. The population standard deviation is 6 = 3.88‘. (Round to two decimal places as needed.) YOU ANSWERED: 4.09 Page 2 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 4, Use the contingency table to the right to determine the probability of events. a. What is the probability of event A'? B B ’ % b. What is the probability of event A and B? A 40 60 c. What is the probability of event A’ and B "P A I 10 50 d. What is the probability of event A ' or B ’? a. The probability of event A ’ is .375 . (Type an integer or decimal rounded to three decimal places as needed.) b. The probability of event A and B is .250 . (Type an integer or decimal rounded to three decimal places as needed.) c. The probability of event A ’ and B ' is .313 . (Type an integer or decimal rounded to three decimal places as needed.) (:1. The probability of event A ’ or B ' is .75 . (Type an integer or decimal rounded to three decimal places as needed.) 5, For n=8 and 1t=0.14, What is P(X=3)? P(X = 3) = .0723 (Round to four decimal places as needed.) Page 3 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 6, Given a normal distribution with u = 100 and o = 10, complete parts (a) through (d). Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that X > 95? The probability that X > 95 is .6915 . (Round to four decimal places as needed.) b. What is the probability that X < 80? The probability that X < 80 is .0228 . (Round to four decimal places as needed.) c. What is the probability that X < 75 or X > 105? The probability that X < 75 or X > 105 is .3147 . (Round to four decimal places as needed.) (1. 80% of the values are between what two X-values (symmetrically distributed around the mean)? 80% of the values are greater than 87.2 and less than 112.8 . (Round to two decimal places as needed.) Cumulative standardized normal distribution table (page 1) 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -3.0 0.0014 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084 -2.2 0.0139 0.0136 0.0132 0.0129 0.0125 0.0122 0.0119 0.0116 0.0113 0.0110 -2.1 0.0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143 -2.0 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 -1.9 0.0287 0.0281 0.0274 0.0268 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233 mammnmmnmoowmmmmm Page4 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: 300252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 — 1.15 0.0539 0.0531 0.0544 0.0550 0.0529 0.0522 0.0514 0.0507 0.0501 0.0294 - 1.7 0.0446 0.0436 0.0427 0.0418 0.0409 0.0401 0.0392 0.0384 0.0375 0.0367 -1.6 0.0548 0.0537 0.0526 0.0516 0.0505 0.0495 0.0485 0.0475 0.0465 0.0455 -1.5 0.0668 0.0655 0.0643 0.0630 0.0618 0.0606 0.0594 0.0582 0.0571 0.0559 -1.4 0.0808 0.0793 0.0778 0.0764 0.0749 0.0735 0.0721 0.0708 0.0694 0.0681 -1.3 0.0968 0.0951 0.0934 0.0918 0.0901 0.0885 0.0869 0.0853 0.0838 0.0823 -1.2 0.1151 0.1131 0.1112 0.1093 0.1075 0.1056 0.1038 0.1020 0.1003 0.0985 -1.1 0.1357 0.1335 0.1314 0.1292 0.1271 0.1251 0.1230 0.1210 0.1190 0.1170 -1.0 0.1587 0.1562 0.1539 0.1515 0.1492 0.1469 0.1446 0.1423 0.1401 0.1379 -0.9 0.1841 0.1814 0.1788 0.1762 0.1736 0.1711 0.1685 0.1660 0.1635 0.1611 -0.8 0.2119 0.2090 0.2061 0.2033 0.2005 0.1977 0.1949 0.1922 0.1894 0.1867 -0.7 0.2420 0.2388 0.2358 0.2327 0.2296 0.2266 0.2236 0.2206 0.2177 0.2148 -0.6 0.2743 0.2709 0.2676 0.2643 0.2611 0.2578 0.2546 0.2514 0.2482 0.2451 -0.5 0.3085 0.3050 0.3015 0.2981 0.2946 0.2912 0.2877 0.2843 0.2810 0.2776 -0.4 0.3446 0.3409 0.3372 0.3336 0.3300 0.3264 0.3228 0.3192 0.3156 0.3121 -0.3 0.3821 0.3783 0.3745 0.3707 0.3669 0.3632 0.3594 0.3557 0.3520 0.3483 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 -0.0 0.5000 0.4960 0.4920 0.4880 0.4840 0.4801 0.4761 0.4721 0.4681 0.4641 6. (cont) Cumulative standaIdized normal distribution table (page 2) Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7518 0.7549 0.7612 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 0.8438 0.8461 0.8485 0.8508 0.8531 0.8554 0.8577 0.8599 0.8621 0.8665 0.8686 0.8708 0.8729 0.8749 0.8770 0.8790 0.8810 0.8830 0.8869 0.8888 0.8907 0.8925 0.8944 0.8962 0.8980 0.8997 0.9015 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 0.9177 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319 0.9345 0.9357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 0.9441 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 0.9545 mmnmommmmmmq Page 5 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: 300252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 1.! U.)’33‘1 UJ’DO‘I- UJ’DIJ Ub’DéZ. U.3351 UJ'Db’y UJ'OUG U310“) U.)’OZ.D U.)’OJ.‘) 1.8 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9699 0.9706 1.9 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767 2.0 0.9772 0.9778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 0.9812 0.9817 2.1 0.9821 0.9826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0.9857 2.2 0.9861 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 2.3 0.9893 0.9896 0.9898 0.9901 0.9904 0.9906 0.9909 0.9911 0.9913 0.9916 2.4 0.9918 0.9920 0.9922 0.9925 0.9927 0.9929 0.9931 0.9932 0.9934 0.9936 2.5 0.9938 0.9940 0.994] 0.9943 0.9945 0.9946 0.9948 0.9949 0.9951 0.9952 2.6 0.9953 0.9955 0.9956 0.9957 0.9959 0.9960 0.9961 0.9962 0.9963 0.9964 2.7 0.9965 0.9966 0.9967 0.9968 0.9969 0.9970 0.9971 0.9972 0.9973 0.9974 2.8 0.9974 0.9975 0.9976 0.9977 0.9977 0.9978 0.9979 0.9979 0.9980 0.9981 2.9 0.9981 0.9982 0.9982 0.9983 0.9984 0.9984 0.9985 0.9985 0.9986 0.9986 3.0 0.9987 0.9987 0.9987 0.9988 0.9988 0.9989 0.9989 0.9989 0.9990 0.9990 6. (cont) Page 6 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 7, Given a normal distribution with u= 55 and o = 4, complete parts (a) through (d). Click here to View page 1 of the cumulative standardized normal distribution table. Click here to View page 2 of the cumulative standardized normal distribution table. a. What is the probability that X > 49? P(X > 49) = .9332 (Round to four decimal places as needed.) b. What is the probability that X < 47? P(X < 47) = .0228 (Round to four decimal places as needed.) c. For this distribution, 9% of the values are less than what X-value? X = 50 (Round to the nearest integer as needed.) (1. Between what two X-values (symmetrically distributed around the mean) are 60% of the values? For this distribution, 60% of the values are between X = 52 and X = 58 . (Round to the nearest integer as needed.) Cumulative standardized normal distribution table, page 1. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -3.0 0.0014 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084 -2.2 0.0139 0.0136 0.0132 0.0129 0.0125 0.0122 0.0119 0.0116 0.0113 0.0110 -2.1 0.0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143 -2.0 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 - 1.9 0.0287 0.0281 0.0274 0.0268 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233 - 1.8 0.0359 0.0351 0.0344 0.0336 0.0329 0.0322 0.0314 0.0307 0.0301 0.0294 - 1.7 0.0446 0.0436 0.0427 0.0418 0.0409 0.0401 0.0392 0.0384 0.0375 0.0367 - 1.6 0.0548 0.0537 0.0526 0.0516 0.0505 0.0495 0.0485 0.0475 0.0465 0.0455 - 1.5 0.0668 0.0655 0.0643 0.0630 0.0618 0.0606 0.0594 0.0582 0.0571 0.0559 - 1.4 0.0808 0.0793 0.0778 0.0764 0.0749 0.0735 0.0721 0.0708 0.0694 0.0681 Page 7 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 7. - 1.3 0.0968 0.0951 0.0934 0.0918 0.0901 0.0885 0.0869 0.0853 0.0838 0.0823 (cont) - 1.2 0.1151 0.1131 0.1112 0.1093 0.1075 0.1056 0.1038 0.1020 0.1003 0.0985 -1.10.1357 0.1335 0.1314 0.1292 0.1271 0.1251 0.1230 0.1210 0.1190 0.1170 - 1.0 0.1587 0.1562 0.1539 0.1515 0.1492 0.1469 0.1446 0.1423 0.1401 0.1379 -0.9 0.1841 0.1814 0.1788 0.1762 0.1736 0.1711 0.1685 0.1660 0.1635 0.1611 -0.8 0.2119 0.2090 0.2061 0.2033 0.2005 0.1977 0.1949 0.1922 0.1894 0.1867 -0.7 0.2420 0.2388 0.2358 0.2327 0.2296 0.2266 0.2236 0.2206 0.2177 0.2148 -0.6 0.2743 0.2709 0.2676 0.2643 0.2611 0.2578 0.2546 0.2514 0.2482 0.2451 -0.5 0.3085 0.3050 0.3015 0.2981 0.2946 0.2912 0.2877 0.2843 0.2810 0.2776 -0.4 0.3446 0.3409 0.3372 0.3336 0.3300 0.3264 0.3228 0.3192 0.3156 0.3121 -0.3 0.3821 0.3783 0.3745 0.3707 0.3669 0.3632 0.3594 0.3557 0.3520 0.3483 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 -0.0 0.5000 0.4960 0.4920 0.4880 0.4840 0.4801 0.4761 0.4721 0.4681 0.4641 Cumulative standardized normal distribution table, page 2. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7518 0.7549 0.7 0.7580 0.7612 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 1.0 0.8413 0.8438 0.8461 0.8485 0.8508 0.8531 0.8554 0.8577 0.8599 0.8621 1.1 0.8643 0.8665 0.8686 0.8708 0.8729 0.8749 0.8770 0.8790 0.8810 0.8830 1.2 0.8849 0.8869 0.8888 0.8907 0.8925 0.8944 0.8962 0.8980 0.8997 0.9015 1.3 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 0.9177 1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319 1.5 0.9332 0.9345 0.9357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 0.9441 1.6 0.9452 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 0.9545 1.7 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 0.9633 1.8 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9699 0.9706 1.9 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767 2.0 0.9772 0.9778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 0.9812 0.9817 2.1 0.9821 0.9826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0.9857 Page 8 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 7. 2.2 0.9861 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 (cont) 2.3 0.9893 0.9896 0.9898 0.9901 0.9904 0.9906 0.9909 0.9911 0.9913 0.9916 2.4 0.9918 0.9920 0.9922 0.9925 0.9927 0.9929 0.9931 0.9932 0.9934 0.9936 2.5 0.9938 0.9940 0.9941 0.9943 0.9945 0.9946 0.9948 0.9949 0.9951 0.9952 2.6 0.9953 0.9955 0.9956 0.9957 0.9959 0.9960 0.9961 0.9962 0.9963 0.9964 2.7 0.9965 0.9966 0.9967 0.9968 0.9969 0.9970 0.9971 0.9972 0.9973 0.9974 2.8 0.9974 0.9975 0.9976 0.9977 0.9977 0.9978 0.9979 0.9979 0.9980 0.9981 2.9 0.9981 0.9982 0.9982 0.9983 0.9984 0.9984 0.9985 0.9985 0.9986 0.9986 3.0 0.9987 0.9987 0.9987 0.9988 0.9988 0.9989 0.9989 0.9989 0.9990 0.9990 8, Given a normal distribution with u = 101 and o = 10, and given you select a sample of n = 25, complete parts (a) through (d). a. What is the probability that i is less than 95? P(i< 95) = .0013 (Type an integer or decimal rounded to four decimal places as needed.) b. What is the probability that i is between 95 and 96.5? 9(95 <E< 96.5) = .0109 (Type an integer or decimal rounded to four decimal places as needed.) c. What is the probability that i is above 102? P(i> 102): 03085 (Type an integer or decimal rounded to four decimal places as needed.) (1. There is a 65% chance that i is above what value? X = 100.23‘ (Type an integer or decimal rounded to two decimal places as needed.) YOU ANSWERED: .1587 100.75 Page 9 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 9, Given a population of returns on endowment for private universities in one fiscal year, indicate what the sampling distribution for samples of 30 would consist of. Choose the correct answer below. iii-A. The sampling distribution is a representative collection of 30 samples, each containing 30 returns, selected with replacement. 2: :- B. The sampling distribution is the average result from all possible samples of 30 returns. iii-C. The sampling distribution is a representative collection of 30 samples, each containing 30 returns, selected without replacement. a!" D. The sampling distribution is the distribution of the results for all possible samples of 30 returns. Page 10 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: eco252 — Fall 2013 10. Book: Berenson: Basic Business Statistics, 126 The amount of time a bank teller spends with each customer has a population mean, u, of 2.80 minutes and a standard deviation, 6, of 0.50 minute. Complete parts (a) through (d). Click here to View page 1 of the cumulative standardized normal distribution table. Click here to View page 2 of the cumulative standardized normal distribution table. a. If you select a random sample of 16 customers, what is the probability that the mean time spent per customer is at least 2.6 minutes? .9452 (Round to four decimal places as needed.) I}. If you select a random sample of 16 customers, there is an 87% chance that the sample mean is less than how many minutes? 2.9413 (Round to four decimal places as needed.) c. What assumption must you make in order to solve (a) and (b)? {ii-A. That the population is uniformly distributed gal B. That the sample is symmetrically distributed such that the Central Limit Theorem will likely hold {ii-C. That the population is normally distributed :jjjz- D. That the sample is normally distributed 3'? E. That the population is symmetrically distributed such that the Central Limit Theorem will likely hold for samples of size 16 d. If you select a random sample of 64 customers, there is an 87% chance that the sample mean is less than how many minutes? 2.8706 (Round to four decimal places as needed.) Area under the cumulative standardized normal distribution from -infinity to Z Cumulative Probabilities 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 — 6.0 0.000000001 — 5.5 0000000019 — 5.0 0.000000287 — 4.5 0.000003398 - 4.0 0000031671 - 3.9 0.00005 0.00005 0.00004 0.00004 0.00004 0.00004 0.00004 0.00003 0.00003 0.00003 — 3.8 0.00007 0.00007 0.00007 0.00006 0.00006 0.00006 0.00006 0.00005 0.00005 0.00005 Page 11 Student: JT Groses Instructor: Vernon Gerety Assignment: Quiz 1 - MyStatLab Submitted: 09/ 15/13 3:12pm Course: 300252 — Fall 2013 Book: Berenson: Basic Business Statistics, 126 10. — 3.7 0.00011 0.00010 0.00010 0.00010 0.00009 0.00009 0.00008 0.00008 0.00008 0.00008 (cont) — 3.6 0.00016 0.00015 0.00015 0.00014 0.00014 0.00013 0.00013 0.00012 0.00012 0.00011 — 3.5 0.00023 0.00022 0.00022 0.00021 0.00020 0.00019 0.00019 0.00018 0.00017 0.00017 - 3.4 0.00034 0.00032 0.00031 0.00030 0.00029 0.00028 0.00027 0.00026 0.00025 0.00024...
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