Unformatted text preview: (aq) was added and a white precipitate was formed. The white precipitate was Hg 2 Cl 2(s) because it is insoluble according to the chloride solubility rule. Upon the addition of 6M NH 3 the white precipitate turned to a gray- black precipitate. Hg 2 2+ (aq) was present in the original unknown sample. Ag + is absent In Step 1-E, 6 M HNO 3(aq) was added to the decantate from step 1- D1 and a colorless solution remained. Ag + (aq) was absent in the original unknown sample. A white precipitate, AgCl (s) , would have been observed if Ag + (aq) had been in the original unknown sample....
View Full Document
- Spring '08
- Solubility, white precipitate, original unknown sample