problem16_01

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
16.1: a) = = = A p p m f v then , 1000 if ) b . 344 . 0 ) Hz 100 ( s) m 344 ( λ 0 0 1000 A Therefore, the amplitude is m. 10 2 . 1 5 - × max max increasing , Since c) p BkA p = while keeping A constant requires decreasing k , and increasing
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: π , by the same factor. Therefore the new wavelength is Hz. 50 m, 9 . 6 ) 20 ( m) 688 . ( m 9 . 6 s m 344 new = = = f...
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online