problem16_08

University Physics with Modern Physics with Mastering Physics (11th Edition)

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16.8: a), b), c) Using Eq. ( 29 , 10 . 16 ( 29 ( 29 ( 29 ( 29 s m 10 32 . 1 mol kg 10 02 . 2 K 15 . 300 K mol J 3145 . 8 41 . 1 3 3 2 H × = × = - v ( 29 ( 29 ( 29 ( 29 s m 10 02 . 1 mol kg 10 00 . 4 K 15 . 300 K mol J 3145 . 8 67 . 1 3 3 e H × = × = - v ( 29 ( 29 ( 29 ( 29 . s m 323 mol kg 10 9 . 39 K 15 . 300 K mol J 3145 . 8 67 . 1 3 Ar = × = - v d) Repeating the calculation of Example 16.5 at
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Unformatted text preview: K 15 . 300 = T gives , s m 348 air = v and so air He air H 94 . 2 , 80 . 3 2 v v v v = = and . 928 . air Ar v v =...
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