problem16_15

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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16.15: a) See Exercise 16.14. The amplitude is 2 2 ρΒω Ι = Α m. 10 44 . 9 Hz)) 3400 ( 2 ( Pa) 10 18 . 2 )( m kg 1000 ( ) m W 10 00 . 3 ( 2 11 2 9 3 2 6 - - × = × × = π The wavelength is m. 434 . 0 Hz 3400 ) m kg (1000 Pa) 10 18 . 2 ( 3 9 = × = = = λ f ρ B f v b) Repeating the above with Pa 10 40 . 1 γ 5 × = = p B and the density of air gives m. 0.100 and m 10 66 . 5 9 = λ × = -
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• 0.100 M, 9 m, 6 W, 0.434 m, dense air molecules

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