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The Research of Doing Exercises-- University of Utah undergraduate studentsdoing exercises per weekOIS 2340 -003Ke Lin (u0778544)Jing Zhou (u0777998)Xiantong Wang (u0784189)Yajing Sun (u0777995) 1 / 9
Executive Summary. How we collected dataⅠSeveral days ago, we did a research about a sample of the time of doing exercise ofundergraduate students in the University of Utah. In order to collect statistics, we made more than150 questionnaires and gave them out to a random of students and most of them were very active incompleting our question. By asking them one simple question that “How much time do you spendin doing exercises per week”? we finally got 118 answers back from them. The reason why wechose questionnaires as our method is that it can help us collect a large amount of data and theresults are more universal and real. After we got these results, we put them into Excel. By usingequations and what we have learned in class, we calculated some necessary statistics, such as mean,standard deviation and standard error of mean. . Objective and DescriptionⅡIn order to know how long do colleges students spend in doing exercises every week, we didthis survey. By analyzing the original statistics we collected and the Excel outputs, then we decidedthe confidence level and alpha, we made our hypothesis. We considered null hypothesis as theaverage hours of doing exercises per week is 9 hours or more, and our alternative hypothesis is theaverage time of doing exercises per week is less than 9 hours. By calculating these data, we gotsome results to help us prove our hypothesis. . Results and MeaningsⅢWe chose the sample size of 118 undergraduate students of the University of Utah, and bycomputing the hours they told us in the Excel sheet, we calculated the sample mean of 9.58, thestandard deviation of 5, and standard error of 0.46. And then we used these data to calculate theconfidence interval, which is (8.68, 10.48). It means when confidence level is 95%, there are 95%probabilities that the actual mean is within 8.68 and 10.48. Furthermore, we also found test statisticsand by looking up in z- value chart, we got p-value equals to 0.8962. P-value indicates theprobability when our null hypothesis is rejected. In other words, there is an 89.62% chance of the