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Experiment 4: Kirchhoff’s Laws
Name:
___Josh Haynes_________
Pledge: __
Josh Haynes
________
ID:
_
__904321944__________
Date: _
__5/30/07____________
Procedure
V
1
D
C
=
9
V
R
1
8
. 2
k
R
2
4
. 7
k
R
3
1
0
k
0
C
B
A
D
Figure 1: Circuit for verifying Kirchhoff’s laws.
Analysis:
1.
Calculate
AB
V
,
DA
V
,
DA
I
,
2
I
and
3
I
where I
2
and I
3
are the currents in
R
2
and
R
3
, respectively, as
identified in Figure 1.
Use the passive sign convention to determine the direction of positive current
flow for
2
I
and
3
I
.
AB
V
= 2.524 V
DA
V
= 6.478 V
DA
I
= .790 mA
2
I
= .537 mA
3
I
= .253 mA
2.
Verify that
DA
2
3
0
I
I
I

+
+
=
.
.790 = .537 + .253, yes
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3.
Verify that
CD
DA
AB
0
V
V
V
+
+
=
. (Note that
CD
s
1
V
V
V
=
=
.)
9v + 6.478 + 2.524 = 9.002, the .002 is a rounding error.
4.
Calculate the power dissipated in each resistor and the total power dissipated (
dis
P
) in the circuit. Be
sure to follow the passive sign convention.
dis
P
= 7.12 mW
5.
Calculate the power generated (
gen
P
) by the source,
s
V
.
gen
P
= 7.11 mW, the .001 mW is
another rounding error
6.
Does the total power generated equal the total power dissipated?
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 Fall '07
 LKPendleton
 Volt, Kirchhoff, Experimental Error

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