problem16_49

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
16.49: a) Combining Eq. (16.14) and Eq. (16.15), 20 . 5 2 12 3 ) 10 ( 0 max 10 ) m W )(10 s m 344 )( m kg 20 . 1 ( 2 10 2 - = = β ρvI p Pa, 10 144 . 1 2 - × = or Pa, 10 14 . 1 2 - × = to three figures. b) From Eq. (16.5), and as in Example 16.1, ( 29 m. 10 51 . 7 Hz 587 Pa) 10 42 . 1 ( 2 s) m 344 ( Pa) 10 144 . 1 ( 2 9 5 2 max max - - × = × × = = = π πf B v p Bk p A c) The distance is proportional to the reciprocal of the square root of the intensity, and
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: hence to 10 raised to half of the sound intensity levels divided by 10. Specifically, m. 9 . 62 m)10 00 . 5 ( 2 3.00) (5.20 =-...
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online