problem16_56

University Physics with Modern Physics with Mastering Physics (11th Edition)

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16.56: a) The cross-section area of the string would be , m 10 1.29 Pa) 10 (7.0 N) (900 2 6 8 - × = × = a corresponding to a radius of mm 640 . 0 (keeping extra figures). The length is the volume divided by the area, m. 40 . 0 ) m
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Unformatted text preview: 10 29 . 1 )( m kg 10 (7.8 kg) 10 00 . 4 ( 2 6 3 3 3 = = = =--a m a V L b) Using the above result in Eq. (16.35) gives Hz 380 or Hz, 377 1 = f to two figures....
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