problem16_57

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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16.57: a) The second distance is midway between the first and third, and if there are no other distances for which resonance occurs, the difference between the first and third positions is the wavelength m. 750 . 0 = λ (This would give the first distance as cm, 75 . 18 4 = λ but at the end of the pipe, where the air is not longer constrained to move along the tube axis, the pressure node and displacement antinode will not coincide exactly
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Unformatted text preview: with the end). The speed of sound in the air is then s. m 375 m) Hz)(0.750 500 ( = = λ = f v b) Solving Eq. (16.10) for , γ . 39 . 1 K) K)(350.15 mol J 3145 . 8 ( s) m mol)(375 kg 10 8 . 28 ( γ 2 3 2 = ⋅ × = =-RT Mv c) Since the first resonance should occur at m 875 . 4 = τ but actually occurs at m, 18 . the difference is m. 0075 ....
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• Standing wave, kg mol, pressure node

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