University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 16.59: a) From Eq. (15.35), with m the mass of the string and M the suspended mass, f1 = F Mg = = 4mL d 2 L2 (420.0 10-3 kg)(9.80 m s 2 ) = 77.3 Hz (225 10 - 6 m)2 (0.45 m)2 (21.4 103 kg m 3 ) and the tuning fork frequencies for which the fork would vibrate are integer multiples of 77.3 Hz. b) The ratio m M 9 10 -4 , so the tension does not vary appreciably along the string. ...
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