problem16_72

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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16.72: a) As in Problem 16.71, , s m 10 2 . 1 Hz 10 4.568 Hz 10 018 . 0 ) s m 10 00 . 3 ( 6 8 14 8 S R S × - = × × - × = - = f f f c v with the minus sign indicating that the gas is approaching the earth, as is expected since . S R f f b) The radius is (952 yr) 10 3.6 s) m 10 2 . 1 )( yr s 10 156 . 3 ( 16 6 7 × = × × 3.8 m = ly . This may also be obtained from (952 yr) . S S R f f f - c) The ratio of the width of the nebula to π 2 times the distance from the earth is the ratio of the angular width
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Unformatted text preview: (taken as 5 arc minutes) to an entire circle, which is 360 60 × arc minutes. The distance to the nebula is then (keeping an extra figure in the intermediate calculation) ly, 10 2 . 5 5 (360) (60) ly 75 . 3 2 3 × = × × so the explosion actually took place about 4100 B.C...
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