Tutorial 3 Questions - PHY1010 Tutorial 3 Forces x x x G...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1 PHY1010 - Tutorial 3 Forces Forces are vector quantities that could cause acceleration: m F a net (Newton’s Second Law). An object is in translational equilibrium (stationary or moving with constant velocity) if vector sum of all the forces acting on it is equal to zero. Free body diagrams represent the object as a particle at the origin of a coordinate system. Force vectors are drawn with their tails on the particle. Problem 1 - A heavy wooden block is dragged by a force F along a rough steel plate, as shown in the diagrams for two cases. The magnitude of the applied force F is the same for both cases. The normal force in (ii), as compared with the normal force in (i) is: (a) the same (b) greater (c) less (d) less for some angles of the incline and greater for others (e) less or greater, depending on the magnitude of F Problem 2 - A crane operator lowers a 16,000 N steel ball with a downward acceleration of 3.00 m/s 2 . Calculate the tension in the cable. Answer: 11.1 kN Problem 3 - A 25-kg crate is pushed across a frictionless horizontal floor with a force of 20 N, directed 20° below the horizontal. Calculate the acceleration of the crate and the normal force on the crate.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern