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hw4-5 - CME211 Fluid Mechanics HW#4 Solution 6:83 Plot...

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Unformatted text preview: CME211 Fluid Mechanics HW#4 Solution 6:83 Plot shown below. Data computed as faflows. Ft. 1: Tank surface w PL 2: Dutairie nozz‘ze »Ref. level at D. 2 m. 1: z'1=1f}.U m; i120; fl =fl Sac Promem 6.?2 for data. 2g 2/ 1 - .3 2 2 2 PL A: is», “$135140 11:; i=——(3'502W83 fi+fi.625 m = E: E: ”D 2g 2(931w5 ) 2g 2g 2g - 2 E»: = «5,2? kNe’m3 ww0.625m= 32—: gr 8,437 kam y 2 13:. B: 23.9; 13.9 m; i =0-525 m 23 Eli—:mz #31525 m 3! 8.43? Pt. E3: Same 33 $11. A Pt. 1): gr, mi); 5-5; $0,625m; P” m 341:9.375 111 2g 9» M37 Pm: 32mg; 321:040fi‘m = ififlm; 3.2.. =6 2g 2(9.31) y ...
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