17.56:
For this case, the algebra reduces to
C.
1
.
35
)
.K
kg
J
4190
)(
kg
240
.
0
(
)
K
kg
J
390
)(
kg
10
00
.
3
)(
200
((
)
C
0
.
20
)(
kg
J
4190
)(
kg
240
.
0
(
)
C
0
.
100
)(
K
kg
J
390
))(
kg
10
00
.
3
)(
200
((
3
3
°
=

This is the end of the preview.
Sign up
to
access the rest of the document.

**Unformatted text preview: **⋅ + ⋅ × ° + ° ⋅ × =--T...

View
Full Document