problem17_87

University Physics with Modern Physics with Mastering Physics (11th Edition)

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17.87: To save some intermediate calculation, let the third rod be made of fractions 2 1 and f f of the original rods; then ) 0650 . 0 ( and 1 1 2 1 f f f = + . 0580 . 0 ) 0350 . 0 ( 2 = + f These two equations in 2 1 and f f are solved for
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Unformatted text preview: , 1 , 0350 . 0650 . 0350 . 0580 . 1 2 1 f f f-=--= and the lengths are cm 7.00 cm) . 30 ( and cm 23.0 cm) . 30 ( 2 1 = = f f...
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This document was uploaded on 02/05/2008.

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