17.89: a) The change in length is due to the tension and heating ( 29 . αΔT Y A, F T α L ΔL A F AY F L L-= ∆ + = ∆00 for Solving . b) The brass bar is given as “heavy” and the wires are given as “fine,” so it may be assumed that the stress in the bar due to the fine wires does not affect the amount by which the bar expands due to the temperature increase. This means that in the equation
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