# Regula Falsi.docx - PASION, JOHN LARRY S. BSCE 3A...

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PASION, JOHN LARRY S. BSCE 3AInstruction: Compute the given problems below. Use blue pen, and show your complete solution belowthe given problem. Make your solution clear, neat and readable.Solve the Non-linear Equations: USE REGULA FALSI (false position) METHOD.1. f(x) = x3− 2x − 6Use Interval [ 2, 3]USING EXCEL: function, f(x) = x3− 2x – 6 the initial guesses are X1=2 and X2=3Iterationxf(x)02-2131522.117647059-0.73885609632.159068865-0.25346902142.1806993230.00880694252.179972996-9.89908E-0562.179981069-3.79269E-0872.1799810721.65201E-1382.179981072092.1799810720It will be noticed that the function, f(x) = x3− 2x – 6 convergences and its root equal to 2.179981072.
PASION, JOHN LARRY S. BSCE 3A2. f(x) =1/2(5x3− 3x)Use interval [ -3, 3]USING EXCEL: function, f(x) = 1/2(5x3− 3x) the initial guesses are X1=-3 and X2=3Iterationxf(x)0-3-631363200300It will be noticed that the function, f(x) = 1/2(5x3− 3x) convergences and its root equal to 0.
PASION, JOHN LARRY S. BSCE 3A3. f(x) = x2− 7x − 5Use interval [6,7]
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Equals sign, ASCII, Root finding algorithm, False position method, JOHN LARRY S, USE REGULA FALSI