Fall04_hw12

Fall04_hw12 - inductor is: R sL LCR s R I I s H s R + + = =...

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ENEE 204 Fall 2004 HW #12 Due: In class on Tuesday, Nov. 30, 2004 Consider the circuit discussed in class and shown below. Problem 1. a) Show that the transfer function, H(s), if the output is the voltage across the capacitor is: R sL LCR s sLR I V s H s c + + = = 2 ˆ ˆ ) ( . b) Show that the transfer function, H(s), if the output is the voltage across the resistor and inductor is also R sL LCR s sLR s H + + = 2 ) ( , which of course make sense. c) Show that the transfer function, H(s), if the output is the current across the capacitor is: R sL LCR s LCR s I I s H s c + + = = 2 2 ˆ ˆ ) ( . d) Show that the transfer function, H(s), if the output is the current across the resistor is: R sL LCR s sL I I s H s R + + = = 2 ˆ ˆ ) ( . e) Show that the transfer function, H(s), if the output is the current across the
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Unformatted text preview: inductor is: R sL LCR s R I I s H s R + + = = 2 ) ( . Problem 2. Solve for the current on the inductor (including transient and steady state parts) using the boundary conditions, V 1 ) ( and , ) ( L = = V I L , and the source current is A ) 1000 cos( 10 10 ) ( 3 t x t i s-= , and the values of the elements are: C=0.1 F, R=200 and L=16 mH. Plot i L (t) and v L (t) just like in the notes. Problem 3. Replace the resistor with R= 50 , all other values the same. Find i L (t), and plot i L (t) and v L (t) . C L t = 0 R i (t) i =?...
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This note was uploaded on 04/07/2008 for the course ENEE 204 taught by Professor Gomez during the Fall '04 term at Maryland.

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Fall04_hw12 - inductor is: R sL LCR s R I I s H s R + + = =...

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