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Unformatted text preview: inductor is: R sL LCR s R I I s H s R + + = = 2 ) ( . Problem 2. Solve for the current on the inductor (including transient and steady state parts) using the boundary conditions, V 1 ) ( and , ) ( L = = V I L , and the source current is A ) 1000 cos( 10 10 ) ( 3 t x t i s-= , and the values of the elements are: C=0.1 F, R=200 and L=16 mH. Plot i L (t) and v L (t) just like in the notes. Problem 3. Replace the resistor with R= 50 , all other values the same. Find i L (t), and plot i L (t) and v L (t) . C L t = 0 R i (t) i =?...
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This note was uploaded on 04/07/2008 for the course ENEE 204 taught by Professor Gomez during the Fall '04 term at Maryland.
- Fall '04