problem17_p114

University Physics with Modern Physics with Mastering Physics (11th Edition)

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17.114: Equation(17.21) becomes . x T kA H = a) W. 13.3 m) C 140 )( m 10 50 . 2 K)( kg J (380 2 4 = ° × = - H b) Denoting the points as 1 and 2, . 1 2 t T dt dQ mc H H = = - Solving for 2, at x T . 1 2 t T kA mc x T x T + = The mass m is , x ρA so the factor multiplying
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Unformatted text preview: t T in the above expression is m. s 137 = x k c Then, m. C 174 ) s C m)(0.250 s 137 ( m C 140 2 = + = x T...
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