Assignment 3 MEMORANDUM

Assignment 3 MEMORANDUM - positive kurtosis(shown on...

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MEMORANDUM TO: Dr. Brian E. Whitman FROM: Mr. John W. Luff DATE: February 6, 2006 SUBJECT: Exploratory Data Analysis and Regression Analysis When observing the data for THA (shown on attachment 2) I can see that the mean is equal to 147.0246, but that the variable, THA, is slightly skewed to the right, with a normal kurtosis or zero kurtosis (shown on attachment 1). I also notice that THA has a very large spread, spanning from a bin of only 9 to a bin that is over 440 (shown on attachment 1). When observing the data for FE (shown on attachment 2) I can see that the mean is equal to 110.1961, but that the variable, FE, is slightly skewed to the right, with a moderately positive kurtosis (shown on attachment 1). I also notice that FE has a very large spread, spanning from a bin around 128 to a bin over 770 (shown on attachment 1).When observing the data for PH (shown on attachment 2) I can see that the mean is equal to 7.640179, and that the variable, PH, has a skew very close to zero, with a
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Unformatted text preview: positive kurtosis (shown on attachment 2). I also notice that PH has an incredibly small spread, starting at a bin of about 6 and going to a bin that is slightly over 8.5 (shown on attachment 2). * To determine the skew of the above variables, I looked at the graph and observed to which side the bins peaked at, a left peak indicates a right skew, a right peak indicates a left skew, and a middle peak would just be normal skew or zero. To determine the kurtosis of the variables I observed the actual peak of the graph, a large peak meant a positive kurtosis, a low peak meant a negative kurtosis, and an average peak indicated a normal kurtosis. The following chemicals elements have a high correlation to THA (shown on attachment 3): • CA - 0.955599 • MG - 0.942599 For CA: The equation for my R 2 value Is, R 2 = 0.9132 My Significance F value is, y = 0.2172x + 4.8543-My R 2 value for CA is a high goodness to fit value.-My Significance F value is significantly valid....
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