**Unformatted text preview: **T k T ∆ = ∆ Eliminating gives for solving and 1 2 T T ∆ ∆ . 2 ln 1.5 ln 1 1 2 1 1- + ∆ = ∆ k k T T Substitution of numerical values gives , C 37 1 ° = ∆ T and the temperature at the radius where the layers meet is C. 103 C 37 C 140 ° = °-° b) Substitution of this value for 1 T ∆ into the above expression for H H = 1 gives ( 29 ( 29 ( 29 W. 27 C 37 2 ln K mol J 04 . m 00 . 2 2 = ° ⋅ = π H...

View
Full Document

- '
- NoProfessor
- Thermodynamics, Heat, W. H= ln