problem17_p126

University Physics with Modern Physics with Mastering Physics (11th Edition)

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17.126: a) The rates are: W, 280 i) ( W, 0.248 h) s 3600 ( ) C 11 )( m 5 . 1 )( m C h J (54 ii) ( 2 2 = ° ° W, 10 10 . 2 ) m 5 . 1 )( m W (1400 iii) ( 3 2 2 × = W. 116 ) K 309 ( K) 320 )( m 5 . 1 )( K m W 10 (5.67 (iv) 4 4 2 4 2 8 = - × - The total is kW, 50 . 2 with the largest portion due to radiation from the sun. h. L 72 . 3 s m 10 03 . 1 K) kg J 10 42 . 2 )( m kg 1000 ( W 10 50 . 2 b) 3 6 6 3 3 v = × = × × = - ρL P c) Redoing the above calculations with
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Unformatted text preview: = e and the decreased area gives a power of 945 W and a corresponding evaporation rate of h. L 4 . 1 Wearing reflective clothing helps a good deal. Large areas of loose weave clothing also facilitate evaporation....
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This document was uploaded on 02/05/2008.

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