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**Unformatted text preview: **differences in the third figures of some answers. 18.1: a) mol. 3 . 56 ) mol kg 10 400 ( kg) 225 . ( 3 tot = = =-M m n b) Of the many ways to find the pressure, Eq. (18.3) gives Pa. 10 6.81 atm 67.2 L) (20.0 K) K)(291.15 mol atm L 06 mol)(0.082 3 . 56 ( 6 = = = = V nRT p...

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